Y=4x^2-36x+81

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Solution for Y=4x^2-36x+81 equation: 



=4Y^2-36Y+81

We move all terms to the left:

-(4Y^2-36Y+81)=0

We get rid of parentheses

-4Y^2+36Y-81=0

a = -4; b = 36; c = -81;
Δ = b2-4ac
Δ = 362-4·(-4)·(-81)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$Y=\frac{-b}{2a}=\frac{-36}{-8}=4+1/2$

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